Require Left and Right Approaches to Agree
A two-sided limit exists only when both one-sided limits exist and agree.
About 25 minutes, plus any extended practice
Supplied materials
- Paper or a browser scratch area; a calculator is optional unless rounding is requested.
- Supplied teaching case: Near x=0, f(x)=2 for x<0 and f(x)=3 for x>0; f(0)=12. Find the two-sided limit at 0. Candidate answers: (A) The limit is 12 (B) The limit is 2 (C) The limit is 3 (D) The two-sided limit does not exist.
- Independent check inputs: Near x=0, f(x)=3 for x<0 and f(x)=4 for x>0; f(0)=13. Find the two-sided limit at 0. Candidate answers: (A) The limit is 13 (B) The limit is 3 (C) The limit is 4 (D) The two-sided limit does not exist.
Learn the idea
A limit describes nearby approach behavior rather than necessarily a function’s value at the point. One-sided agreement, removable holes and continuity connect algebraic simplification with precise statements about a function’s local behavior. A two-sided limit exists only when both one-sided limits exist and agree. A function’s separately assigned value at the point cannot reconcile different left and right approach values.
Here is the method on the supplied teaching case. The left-hand limit is 2; the right-hand limit is 3. They differ, so no two-sided limit exists. Changing f(0) would not reconcile those approach values.
Do not average the two one-sided limits or substitute the isolated point’s value. Compare the approach values directly; different values imply that the two-sided limit does not exist.
- Write or sketch the supplied teaching case, labeling its quantities and restrictions.
- Apply the method shown in the worked solution, keeping each intermediate equality or justified inference.
- Solve the independent check with its changed inputs before revealing feedback.
- Complete the three practice cases; explain which mathematical rule rules out one distractor in each case.
See the method in action
Teaching case: Near x=0, f(x)=2 for x<0 and f(x)=3 for x>0; f(0)=12. Find the two-sided limit at 0. Candidate answers: (A) The limit is 12 (B) The limit is 2 (C) The limit is 3 (D) The two-sided limit does not exist. Solution: The left-hand limit is 2; the right-hand limit is 3. They differ, so no two-sided limit exists. Changing f(0) would not reconcile those approach values. The final answer is The two-sided limit does not exist. Do not average the two one-sided limits or substitute the isolated point’s value. Compare the approach values directly; different values imply that the two-sided limit does not exist.
Check your reasoning
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Helpful tips
- A two-sided limit exists only when both one-sided limits exist and agree.
- Do not average the two one-sided limits or substitute the isolated point’s value.
See the answer and explanation
The two-sided limit does not exist
The left-hand limit is 3; the right-hand limit is 4. They differ, so no two-sided limit exists. Changing f(0) would not reconcile those approach values.
Take it further
Changed-input task: Near x=0, f(x)=9 for x<0 and f(x)=10 for x>0; f(0)=19. Find the two-sided limit at 0. Candidate answers: (A) The limit is 10 (B) The limit is 19 (C) The limit is 9 (D) The two-sided limit does not exist. Show the mathematical reason, not only the selected answer. Expected result: The two-sided limit does not exist. The left-hand limit is 9; the right-hand limit is 10. They differ, so no two-sided limit exists. Changing f(0) would not reconcile those approach values.
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