Read a Tail Observation as well as an Average
Compare the maximum recorded latency with the average rather than replacing one measure with the other.
About 22 minutes, plus any extended practice
Supplied materials
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Learn the idea
An average latency can hide a slow request. Looking at the ordered distribution or a maximum reveals another aspect of performance. Our small supplied list is not a validated service benchmark or a percentile guarantee; it simply demonstrates why a single average does not describe every observation.
Compare the maximum recorded latency with the average rather than replacing one measure with the other. The maximum in five samples does not certify a production percentile.
Use this supplied case: Paper Python 3 expression: max([1,1,1,1,8]). What value results? The task is to connect the given information to the computing idea. Write a short evidence trail so another learner can reproduce your choice. The simplified case describes the stated model, not every real system.
- Represent the supplied worked case with a labeled drawing, table or short trace.
- Compare the maximum recorded latency with the average rather than replacing one measure with the other.
- Explain why the worked answer fits and why one alternative does not.
- Try the new check and practice cases; revisit the stated rule if your evidence does not match.
See the method in action
Paper Python 3 expression: max([1, 1, 1, 1, 8]). What value results? The supported answer is 8. Tracing the expression under Python 3 rules gives 8. Compare the maximum recorded latency with the average rather than replacing one measure with the other. The maximum in five samples does not certify a production percentile. An average latency can hide a slow request.
Check your reasoning
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Helpful tips
- Compare the maximum recorded latency with the average rather than replacing one measure with the other.
- The maximum in five samples does not certify a production percentile.
See the answer and explanation
10
The observations are [2, 2, 3, 2, 10]. In sorted order they are [2, 2, 2, 3, 10]; the largest is 10. Their mean is 19/5=3.8, which answers a different question. Compare the maximum recorded latency with the average rather than replacing one measure with the other.
Take it further
New latencies[2, 2, 2, 2, 12]seconds have mean 20/5=4 and maximum 12. Neither is a certified production percentile.
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More practice: try new cases
Choose an answer for each problem. Explain your method on paper, then use the feedback to decide what to revisit.
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