Grade 9 · unit review

Review: Conserving atoms and predicting reaction amounts

Use balanced symbolic models, mass boundaries, and stoichiometric ratios.

Bring the unit skills together

Use these 4 new cases to check your reasoning. Choices are temporary and are not saved to an account, sent to staff or recorded as school grades. Download your current review choices before leaving or reloading.

Unit review questions
1. Which equation conserves N and H atom counts?
2. An open boundary begins with 120 g, receives 4 g, and ends with 114 g. Under a complete mass ledger, how much exits?
3. For 2 H₂ + O₂ → 2 H₂O with sufficient H₂ and complete reaction, 3 mol O₂ yields how many mol H₂O?
4. A packet for N₂ + 3 H₂ → 2 NH₃ contains 3 N₂ and 12 H₂ molecules. What forms and remains?

The download contains your current choices and any checked feedback. Keep the separate transfer-task work in your own document; downloading its instructions does not mark it complete.

Use the skills in a new task

Audit a fictional paper reaction report for N₂ + 3 H₂ → 2 NH₃. Its packet has 5 N₂ and 9 H₂ molecules; it claims 10 NH₃ and no leftovers. Correct it using set counts and atom conservation. Separately, scale the balanced equation for 2 mol N₂ with sufficient H₂. A mass ledger starts at 90 g and ends at 86 g inside an open boundary, with no input; explain the difference.

Work on paper or in your own document. Explain the choices you made.

  • Check balanced per-set counts of 2 N and 6 H atoms.
  • Find H₂ limits the packet to three sets, making 6 NH₃ and leaving 2 N₂.
  • For 2 mol N₂, state 6 mol H₂ required and 4 mol NH₃ produced.
  • Account for 4 g exiting the open mass boundary without matter destruction.
Compare with a model response

The equation has 2 N and 6 H per set. Nine H₂ allow only three sets, so the packet makes 6 NH₃ and leaves 2 N₂. Atom totals remain 10 N and 18 H: product has 6 N and 18 H, leftovers add 4 N. For 2 mol N₂ the completion model needs 6 mol H₂ and yields 4 mol NH₃. The separate open ledger has 90 − 86 = 4 g crossing out, rather than matter disappearing.

A different response can also meet the criteria. Compare the evidence and reasoning, rather than copying the wording.