Review: Algebra1: Descriptive Data and Outliers
Data summaries describe center and spread using stated definitions. Mean, median, interquartile range and mean absolute deviation respond differently to extreme values, so the chosen measure should match the question and convention.
Bring the unit skills together
Use these 4 new cases to check your reasoning. Choices are temporary and are not saved to an account, sent to staff or recorded as school grades. Download your current review choices before leaving or reloading.
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Use the skills in a new task
Create a four-part mathematical solution sheet for these supplied cases. 1. For the complete supplied data [9, 10, 11, 12, 23], which pair is (mean, median)? Candidate answers: (A) (11, 13) (B) (13, 11) (C) (13, 12) (D) (23, 11). 2. For sorted data [10, 19, 28, 37, 46, 55], use the median of each three-value half for Q1 and Q3. Find IQR. Candidate answers: (A) 18 (B) 27 (C) 45 (D) 9. 3. For data [9, 18, 27], find mean absolute deviation from the mean, exactly. Candidate answers: (A) 0 (B) 18 (C) 6 (D) 9. 4. Data 9,10,11,12,13 change only by replacing the largest value with 63. Which statement is true? Candidate answers: (A) Both mean and median stay the same (B) The mean decreases (C) The mean increases; the median stays the same (D) The median increases by 50.
Work on paper or in your own document. Explain the choices you made.
- State each requested quantity or relationship and its input restrictions.
- Show intermediate calculations or the applicable theorem with matching correspondences.
- Give all four results, including exact values or requested rounding and units.
- Check a result by substitution, reversal, dimensions, a representation or a counterexample as appropriate.
Compare with a model response
1. (13, 11). The sum is 65; divide by 5 to get mean 13. The third sorted value is the median 11. The high value pulls the mean upward. 2. 27. Q1 is the lower-half middle value 19; Q3 is the upper-half middle 46. Thus IQR=46−19=27, under the stated convention. 3. 6. The mean is 18. Absolute distances are 9,0,9. Their average is (9+0+9)/3=6; signed distances would incorrectly cancel. 4. The mean increases; the median stays the same. The sum increases by 50, so the mean increases by 50/5=10. The middle sorted value remains 11. The outlier affects these centers differently.
A different response can also meet the criteria. Compare the evidence and reasoning, rather than copying the wording.