Retain a Fraction of the Current Amount
A fixed percent decrease preserves the same fraction each period.
About 20 minutes, plus any extended practice
Supplied materials
- Paper or a browser scratch area; a calculator is optional unless rounding is requested.
- Supplied teaching case: A fictional model loses 20% each period from 200. What remains after two periods? Candidate answers: (A) 127 (B) 128 (C) 129 (D) 256.
- Independent check inputs: A fictional model loses 20% each period from 300. What remains after two periods? Candidate answers: (A) 191 (B) 192 (C) 193 (D) 384.
Learn the idea
An exponential pattern changes by a constant multiplicative ratio over equal input steps. This differs from a linear pattern’s constant addition and can model supplied growth, decay or ordered geometric sequence terms. A fixed percent decrease preserves the same fraction each period. The retained fraction multiplies the current amount, so absolute losses get smaller as the remaining amount shrinks.
Here is the method on the supplied teaching case. Each period retains 80%, so multiply by 0.8 twice: 200×0.8²=128. The second loss is based on the smaller current amount.
Losing twenty percent twice does not mean losing forty percent of the original. Track the surviving multiplier at each period, keeping sufficient digits until the final requested rounding.
- Write or sketch the supplied teaching case, labeling its quantities and restrictions.
- Apply the method shown in the worked solution, keeping each intermediate equality or justified inference.
- Solve the independent check with its changed inputs before revealing feedback.
- Complete the three practice cases; explain which mathematical rule rules out one distractor in each case.
See the method in action
Teaching case: A fictional model loses 20% each period from 200. What remains after two periods? Candidate answers: (A) 127 (B) 128 (C) 129 (D) 256. Solution: Each period retains 80%, so multiply by 0.8 twice: 200×0.8²=128. The second loss is based on the smaller current amount. The final answer is 128. Losing twenty percent twice does not mean losing forty percent of the original. Track the surviving multiplier at each period, keeping sufficient digits until the final requested rounding.
Check your reasoning
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Helpful tips
- A fixed percent decrease preserves the same fraction each period.
- Losing twenty percent twice does not mean losing forty percent of the original.
See the answer and explanation
192
Each period retains 80%, so multiply by 0.8 twice: 300×0.8²=192. The second loss is based on the smaller current amount.
Take it further
Changed-input task: A fictional model loses 20% each period from 900. What remains after two periods? Candidate answers: (A) 1152 (B) 575 (C) 576 (D) 577. Show the mathematical reason, not only the selected answer. Expected result: 576. Each period retains 80%, so multiply by 0.8 twice: 900×0.8²=576. The second loss is based on the smaller current amount.
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More practice: try new cases
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