Grade 8 · lesson 4 of 4

Find When Two Linear Rules Agree

Solve an intersection and interpret costs on either side.

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Supplied materials

  • Paper or a note app.
  • Fictional print prices: A = 2x + 6 and B = 3x + 2 dollars; x is a nonnegative whole poster count.

Learn the idea

Two rules agree at an input where both produce the same output. Set their expressions equal: 2x + 6 = 3x + 2. This equation compares complete costs, including both fixed fees and changing parts.

Subtract 2x from both sides and subtract two to find x = 4. The common output is fourteen dollars. Because B rises faster, B is lower before the crossing and higher after it; checking one count on each side makes that interpretation concrete.

  1. Set the two complete cost expressions equal.
  2. Solve 2x + 6 = 3x + 2, then substitute x = 4 into both rules.
  3. Compare both costs at x = 2 and x = 6, then solve the changed pair below.
Worked example

See the method in action

At x = 4, A = 8 + 6 = 14 and B = 12 + 2 = 14. At x = 2, A = 10 and B = 8. At x = 6, A = 18 and B = 20.

Your turn

Check your reasoning

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C = 2x + 9 and D = 3x + 3. At which count do their costs agree?

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See the answer and explanation

6 posters

2x + 9 = 3x + 3 gives 9 = x + 3, so x = 6. Both costs are $21: 12 + 9 = 18 + 3.

Take it further

Change D to 3x + 5 while C stays 2x + 9. Equality now gives x = 4 and a shared cost of $17. Raising D’s fixed fee moves the crossing to a smaller count.

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