Grade 8 · lesson 2 of 4

Calculate Acceleration from Net Force

Apply a = Fnet/m with a stated horizontal model.

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Supplied materials

  • Use the supplied fictional observations or model. Paper and pencil are optional; spoken answers are welcome. No equipment or real experiment is needed.

Learn the idea

Net force changes velocity through acceleration. For constant mass in this model, acceleration a = net force Fnet divided by mass m. Right is positive. A positive acceleration means the velocity changes toward the right; it does not prove that the cart is already moving right. List all horizontal forces before using the equation.

A fictional 2 kg cart has +10 N right and −4 N left, with no other horizontal forces; vertical forces balance. Its horizontal net is +6 N, giving a = 6/2 = +3 m/s². This means its right-positive velocity changes by +3 m/s each second while the forces stay constant. A second 4 kg cart with the same net force would have only +1.5 m/s² acceleration.

  1. Add +10 and −4 N to obtain the horizontal net.
  2. Divide by 2 kg and label the result m/s².
  3. Compare with a 4 kg cart under the same net force.
  4. State why starting velocity is separate information.
Worked example

See the method in action

Fnet = +6 N. For 2 kg, a = +3 m/s²; for 4 kg, a = +1.5 m/s². Doubling the mass halves acceleration for this unchanged net force.

Your turn

Check your reasoning

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A 3 kg model cart has 12 N right and 6 N left, with no other horizontal forces. What is its acceleration?

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See the answer and explanation

2 m/s² right

The net is 12 − 6 = 6 N right; 6/3 = 2 m/s² right.

Take it further

Change the left force to 15 N. Net force becomes −3 N, giving −1 m/s², or 1 m/s² left, for the same 3 kg mass.

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