Calculate a trait frequency
Calculate a trait frequency using supplied evidence and a solved model.
About 25 minutes, plus any extended practice
Supplied materials
- All measurements and observations below are supplied classroom examples. They are not data from actual learners or a claim about a particular real site.
- Paper or browser document; an ordinary calculator is optional.
- Rule: Trait percentage equals 100 times trait count divided by total count. Formula: 100*a/b. Variable key: a = trait count, b = population count
- Distinct worked inputs and result: A distinct population has 12 of 40 individuals with a trait: 100×12/40=30%.
- Assessment case 1: Supplied case 1: trait count=15; population count=50, using the explicitly named quantities. Trait percentage equals 100 times trait count divided by total count. What result follows?
- Assessment case 2: Supplied case 2: trait count=24; population count=60, using the explicitly named quantities. Trait percentage equals 100 times trait count divided by total count. What result follows?
- Assessment case 3: Supplied case 3: trait count=18; population count=40, using the explicitly named quantities. Trait percentage equals 100 times trait count divided by total count. What result follows?
- Assessment case 4: Supplied case 4: trait count=30; population count=75, using the explicitly named quantities. Trait percentage equals 100 times trait count divided by total count. What result follows?
- Assessment case 5: Supplied case 5: trait count=36; population count=80, using the explicitly named quantities. Trait percentage equals 100 times trait count divided by total count. What result follows?
- Assessment case 6: Supplied case 6: trait count=42; population count=70, using the explicitly named quantities. Trait percentage equals 100 times trait count divided by total count. What result follows?
Learn the idea
A frequency counts a specified category divided by a population total. A shift does not alone identify selection: sampling, migration and chance can also contribute.
Trait percentage equals 100 times trait count divided by total count. The formula in the supplied model is 100*a/b. Variable key: a = trait count, b = population count. Use total population as denominator. Count the same trait definition across intervals.
A distinct population has 12 of 40 individuals with a trait: 100×12/40=30%. A frequency change alone does not prove its cause. Track the quantity and unit before calculating. Explain the meaning of a positive, negative or fractional result when relevant. A numerical answer supports the stated model calculation; broader claims require the additional measurements and assumptions described here.
- Name the measured quantities and their units before substituting values.
- Write the stated rule and use the variable key to match each symbol to its explicitly named quantity.
- Calculate each supplied case separately, keeping intermediate arithmetic and the result unit.
- Explain the result in context and identify the assumption that would invalidate direct use of the rule.
See the method in action
Worked distinct example: A distinct population has 12 of 40 individuals with a trait: 100×12/40=30%. Method: identify the quantities in the stated rule, substitute using compatible units, and perform the operations in the correct order. Use total population as denominator. Count the same trait definition across intervals. Interpret the final unit and keep the model assumption visible; this calculation is not a measurement of a real learner or site.
Check your reasoning
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Helpful tips
- Use total population as denominator.
- Count the same trait definition across intervals.
See the answer and explanation
30 %
Substitute the supplied values: 100*(15)/(50) = 30 %. Use total population as denominator. A frequency change alone does not prove its cause.
Take it further
Changed-input task: use the same stated model with trait count=16; population count=50. Expected result: 32 %. Explain what changes and keep this assumption: A frequency change alone does not prove its cause.
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More practice: try new cases
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