Grade 7 · lesson 2 of 4

Multiply Signed Changes

Apply multiplication signs and interpret repeated changes.

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Supplied materials

  • Paper or a note app.
  • Supplied pretend change: −3 units each interval. Products to examine: 4 × (−3), 0 × (−3), and (−4) × (−3).

Learn the idea

Four copies of a negative change make a negative total: 4 × (−3) means −3 + −3 + −3 + −3. This gives −12. One positive factor and one negative factor produce a negative product.

Two negative factors produce a positive product. This is consistent with distributing multiplication over addition: [4 + (−4)] × (−3) = 0. Since the 4 × (−3) part is −12, the other part must be +12 to sum to zero. A negative count is an algebraic extension, not a literal negative number of objects.

  1. Add four copies of −3 to find −12.
  2. Write 4 × (−3) + (−4) × (−3) = 0.
  3. Use the missing opposite +12 to explain the two-negative product, then calculate (−5) × (−3).
Worked example

See the method in action

4 × (−3) = −12 and (−4) × (−3) = +12. Their sum is 0, agreeing with [4 + (−4)] × (−3) = 0.

Your turn

Check your reasoning

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What is (−5) × (−3)?

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See the answer and explanation

15

Both factors are negative, so the product is positive. Their magnitudes multiply to 5 × 3 = 15.

Take it further

Change the first factor to +5. Now (+5) × (−3) = −15. The magnitude stays fifteen while the sign changes because only one factor is negative.

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