Grade 6 · lesson 2 of 4

Calculate frequency from cycles

Calculate frequency from cycles using supplied evidence and a solved model.

About 25 minutes, plus any extended practice

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Supplied materials

  • All measurements and observations below are supplied classroom examples. They are not data from actual learners or a claim about a particular real site.
  • Paper or browser document; an ordinary calculator is optional.
  • Rule: Frequency equals complete cycles divided by seconds. Formula: a/b. Variable key: a = complete cycles, b = duration (s)
  • Distinct worked inputs and result: A distinct record has 24 cycles in 4 seconds: 24/4=6 Hz.
  • Assessment case 1: Supplied case 1: complete cycles=30; duration (s)=3, using the explicitly named quantities. Frequency equals complete cycles divided by seconds. What result follows?
  • Assessment case 2: Supplied case 2: complete cycles=40; duration (s)=5, using the explicitly named quantities. Frequency equals complete cycles divided by seconds. What result follows?
  • Assessment case 3: Supplied case 3: complete cycles=60; duration (s)=4, using the explicitly named quantities. Frequency equals complete cycles divided by seconds. What result follows?
  • Assessment case 4: Supplied case 4: complete cycles=72; duration (s)=6, using the explicitly named quantities. Frequency equals complete cycles divided by seconds. What result follows?
  • Assessment case 5: Supplied case 5: complete cycles=90; duration (s)=5, using the explicitly named quantities. Frequency equals complete cycles divided by seconds. What result follows?
  • Assessment case 6: Supplied case 6: complete cycles=84; duration (s)=7, using the explicitly named quantities. Frequency equals complete cycles divided by seconds. What result follows?

Learn the idea

Frequency is cycles per second, measured in hertz. Count complete cycles and use the measured duration. A wave’s pitch and loudness are not the same property.

Frequency equals complete cycles divided by seconds. The formula in the supplied model is a/b. Variable key: a = complete cycles, b = duration (s). Count cycles, not half-cycle peaks separately. Use seconds for hertz.

A distinct record has 24 cycles in 4 seconds: 24/4=6 Hz. Frequency does not measure loudness. Track the quantity and unit before calculating. Explain the meaning of a positive, negative or fractional result when relevant. A numerical answer supports the stated model calculation; broader claims require the additional measurements and assumptions described here.

  1. Name the measured quantities and their units before substituting values.
  2. Write the stated rule and use the variable key to match each symbol to its explicitly named quantity.
  3. Calculate each supplied case separately, keeping intermediate arithmetic and the result unit.
  4. Explain the result in context and identify the assumption that would invalidate direct use of the rule.
Worked example

See the method in action

Worked distinct example: A distinct record has 24 cycles in 4 seconds: 24/4=6 Hz. Method: identify the quantities in the stated rule, substitute using compatible units, and perform the operations in the correct order. Count cycles, not half-cycle peaks separately. Use seconds for hertz. Interpret the final unit and keep the model assumption visible; this calculation is not a measurement of a real learner or site.

Your turn

Check your reasoning

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Helpful tips
  • Count cycles, not half-cycle peaks separately.
  • Use seconds for hertz.
Supplied case 1: complete cycles=30; duration (s)=3, using the explicitly named quantities. Frequency equals complete cycles divided by seconds. What result follows?

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See the answer and explanation

10 Hz

Substitute the supplied values: (30)/(3) = 10 Hz. Count cycles, not half-cycle peaks separately. Frequency does not measure loudness.

Take it further

Changed-input task: use the same stated model with complete cycles=31; duration (s)=3. Expected result: approximately 10.333333 Hz. Explain what changes and keep this assumption: Frequency does not measure loudness.

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More practice: try new cases

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More practice: try new cases
1. Supplied case 2: complete cycles=40; duration (s)=5, using the explicitly named quantities. Frequency equals complete cycles divided by seconds. What result follows?
Need a hint?
  • Frequency equals complete cycles divided by seconds.
  • Use seconds for hertz.
2. Supplied case 3: complete cycles=60; duration (s)=4, using the explicitly named quantities. Frequency equals complete cycles divided by seconds. What result follows?
Need a hint?
  • Frequency equals complete cycles divided by seconds.
  • Use seconds for hertz.
3. Supplied case 4: complete cycles=72; duration (s)=6, using the explicitly named quantities. Frequency equals complete cycles divided by seconds. What result follows?
Need a hint?
  • Frequency equals complete cycles divided by seconds.
  • Use seconds for hertz.

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