Grade 6 · lesson 3 of 4

Calculate a temperature difference

Calculate a temperature difference using supplied evidence and a solved model.

About 25 minutes, plus any extended practice

Download the grade pack

Supplied materials

  • All measurements and observations below are supplied classroom examples. They are not data from actual learners or a claim about a particular real site.
  • Paper or browser document; an ordinary calculator is optional.
  • Rule: Temperature difference equals warmer Celsius reading minus cooler Celsius reading. Formula: a-b. Variable key: a = warmer temperature (°C), b = cooler temperature (°C)
  • Distinct worked inputs and result: A distinct comparison is 30°C and 22°C: 30-22=8°C difference.
  • Assessment case 1: Supplied case 1: warmer temperature (°C)=40; cooler temperature (°C)=20, using the explicitly named quantities. Temperature difference equals warmer Celsius reading minus cooler Celsius reading. What result follows?
  • Assessment case 2: Supplied case 2: warmer temperature (°C)=35; cooler temperature (°C)=18, using the explicitly named quantities. Temperature difference equals warmer Celsius reading minus cooler Celsius reading. What result follows?
  • Assessment case 3: Supplied case 3: warmer temperature (°C)=50; cooler temperature (°C)=25, using the explicitly named quantities. Temperature difference equals warmer Celsius reading minus cooler Celsius reading. What result follows?
  • Assessment case 4: Supplied case 4: warmer temperature (°C)=28; cooler temperature (°C)=16, using the explicitly named quantities. Temperature difference equals warmer Celsius reading minus cooler Celsius reading. What result follows?
  • Assessment case 5: Supplied case 5: warmer temperature (°C)=60; cooler temperature (°C)=32, using the explicitly named quantities. Temperature difference equals warmer Celsius reading minus cooler Celsius reading. What result follows?
  • Assessment case 6: Supplied case 6: warmer temperature (°C)=45; cooler temperature (°C)=21, using the explicitly named quantities. Temperature difference equals warmer Celsius reading minus cooler Celsius reading. What result follows?

Learn the idea

A difference compares two temperature readings in the same scale. A Celsius interval has the same size as a kelvin interval, but the zero points differ.

Temperature difference equals warmer Celsius reading minus cooler Celsius reading. The formula in the supplied model is a-b. Variable key: a = warmer temperature (°C), b = cooler temperature (°C). Use warmer minus cooler for a positive difference. A difference is not a total energy amount.

A distinct comparison is 30°C and 22°C: 30-22=8°C difference. Do not compare mixed temperature scales directly. Track the quantity and unit before calculating. Explain the meaning of a positive, negative or fractional result when relevant. A numerical answer supports the stated model calculation; broader claims require the additional measurements and assumptions described here.

  1. Name the measured quantities and their units before substituting values.
  2. Write the stated rule and use the variable key to match each symbol to its explicitly named quantity.
  3. Calculate each supplied case separately, keeping intermediate arithmetic and the result unit.
  4. Explain the result in context and identify the assumption that would invalidate direct use of the rule.
Worked example

See the method in action

Worked distinct example: A distinct comparison is 30°C and 22°C: 30-22=8°C difference. Method: identify the quantities in the stated rule, substitute using compatible units, and perform the operations in the correct order. Use warmer minus cooler for a positive difference. A difference is not a total energy amount. Interpret the final unit and keep the model assumption visible; this calculation is not a measurement of a real learner or site.

Your turn

Check your reasoning

Your answer is temporary and is not saved to an account. Download your current answer before leaving or reloading. Written work on paper or in another app stays in your own file.

Helpful tips
  • Use warmer minus cooler for a positive difference.
  • A difference is not a total energy amount.
Supplied case 1: warmer temperature (°C)=40; cooler temperature (°C)=20, using the explicitly named quantities. Temperature difference equals warmer Celsius reading minus cooler Celsius reading. What result follows?

Feedback appears here after you check. This is practice, not a graded school assessment.

See the answer and explanation

20 °C

Substitute the supplied values: (40)-(20) = 20 °C. Use warmer minus cooler for a positive difference. Do not compare mixed temperature scales directly.

Take it further

Changed-input task: use the same stated model with warmer temperature (°C)=41; cooler temperature (°C)=20. Expected result: 21 °C. Explain what changes and keep this assumption: Do not compare mixed temperature scales directly.

Nothing here is saved to an account or sent to a teacher. The answer download includes your current choice and any checked feedback. It does not include choices from the separate More practice section. Download that section separately.

More practice: try new cases

Choose an answer for each problem. Explain your method on paper, then use the feedback to decide what to revisit.

More practice: try new cases
1. Supplied case 2: warmer temperature (°C)=35; cooler temperature (°C)=18, using the explicitly named quantities. Temperature difference equals warmer Celsius reading minus cooler Celsius reading. What result follows?
Need a hint?
  • Temperature difference equals warmer Celsius reading minus cooler Celsius reading.
  • A difference is not a total energy amount.
2. Supplied case 3: warmer temperature (°C)=50; cooler temperature (°C)=25, using the explicitly named quantities. Temperature difference equals warmer Celsius reading minus cooler Celsius reading. What result follows?
Need a hint?
  • Temperature difference equals warmer Celsius reading minus cooler Celsius reading.
  • A difference is not a total energy amount.
3. Supplied case 4: warmer temperature (°C)=28; cooler temperature (°C)=16, using the explicitly named quantities. Temperature difference equals warmer Celsius reading minus cooler Celsius reading. What result follows?
Need a hint?
  • Temperature difference equals warmer Celsius reading minus cooler Celsius reading.
  • A difference is not a total energy amount.

Your choices are temporary. Feedback appears after you check all the answers.

Nothing here is saved to an account or sent to a teacher. Keep your own notes or download them before leaving. The score describes these questions; it does not certify subject mastery.

Check the subject sources

These LifeStarter passages, scenarios and exercises are authored for this Academy with AI assistance and review. External resources keep their publishers’ terms. A grade label suggests a starting level; it does not establish alignment with your school’s complete requirements.