Grade 12 · lesson 1 of 4

Recover a Squared Trigonometric Value

Unit-circle coordinates satisfy x²+y²=1, giving cos²θ+sin²θ=1.

About 25 minutes, plus any extended practice

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Supplied materials

  • Paper or a browser scratch area; a calculator is optional unless rounding is requested.
  • Supplied teaching case: If sin θ=2/3, find cos²θ exactly. Candidate answers: (A) 1/3 (B) 13/9 (C) 4/9 (D) 5/9.
  • Independent check inputs: If sin θ=3/4, find cos²θ exactly. Candidate answers: (A) 1/4 (B) 25/16 (C) 7/16 (D) 9/16.

Learn the idea

An identity holds for all inputs in its domain, while an equation asks for particular angle solutions. Algebraic identities, angle formulas and geometric laws must retain signs, intervals and their defining conditions. Unit-circle coordinates satisfy x²+y²=1, giving cos²θ+sin²θ=1. A known sine determines cosine squared, but not cosine’s sign without quadrant information.

Here is the method on the supplied teaching case. The identity sin²θ+cos²θ=1 gives cos²θ=1−(2/3)²=5/9. It determines the square, while the sign of cos θ would still require quadrant information.

Do not take a signed cosine value from its square alone. The identity uses squared values, so subtract sin²θ rather than sinθ; the supplied result is an exact rational square quantity.

  1. Write or sketch the supplied teaching case, labeling its quantities and restrictions.
  2. Apply the method shown in the worked solution, keeping each intermediate equality or justified inference.
  3. Solve the independent check with its changed inputs before revealing feedback.
  4. Complete the three practice cases; explain which mathematical rule rules out one distractor in each case.
Worked example

See the method in action

Teaching case: If sin θ=2/3, find cos²θ exactly. Candidate answers: (A) 1/3 (B) 13/9 (C) 4/9 (D) 5/9. Solution: The identity sin²θ+cos²θ=1 gives cos²θ=1−(2/3)²=5/9. It determines the square, while the sign of cos θ would still require quadrant information. The final answer is 5/9. Do not take a signed cosine value from its square alone. The identity uses squared values, so subtract sin²θ rather than sinθ; the supplied result is an exact rational square quantity.

Your turn

Check your reasoning

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Helpful tips
  • Unit-circle coordinates satisfy x²+y²=1, giving cos²θ+sin²θ=1.
  • Do not take a signed cosine value from its square alone.
If sin θ=3/4, find cos²θ exactly.

Feedback appears here after you check. This is practice, not a graded school assessment.

See the answer and explanation

7/16

The identity sin²θ+cos²θ=1 gives cos²θ=1−(3/4)²=7/16. It determines the square, while the sign of cos θ would still require quadrant information.

Take it further

Changed-input task: If sin θ=9/10, find cos²θ exactly. Candidate answers: (A) 1/10 (B) 181/100 (C) 19/100 (D) 81/100. Show the mathematical reason, not only the selected answer. Expected result: 19/100. The identity sin²θ+cos²θ=1 gives cos²θ=1−(9/10)²=19/100. It determines the square, while the sign of cos θ would still require quadrant information.

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More practice: try new cases

Choose an answer for each problem. Explain your method on paper, then use the feedback to decide what to revisit.

More practice: try new cases
1. If sin θ=4/5, find cos²θ exactly.
Need a hint?
  • Unit-circle coordinates satisfy x²+y²=1, giving cos²θ+sin²θ=1.
  • Do not take a signed cosine value from its square alone.
2. If sin θ=5/6, find cos²θ exactly.
Need a hint?
  • Unit-circle coordinates satisfy x²+y²=1, giving cos²θ+sin²θ=1.
  • Do not take a signed cosine value from its square alone.
3. If sin θ=6/7, find cos²θ exactly.
Need a hint?
  • Unit-circle coordinates satisfy x²+y²=1, giving cos²θ+sin²θ=1.
  • Do not take a signed cosine value from its square alone.

Your choices are temporary. Feedback appears after you check all the answers.

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