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Grade 11 · unit review

Review: Circuits, Current and Resistance

Calculate idealized circuit quantities without electrical construction.

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Bring the unit skills together

Use these 4 new cases to check your reasoning. Choices are temporary and are not saved to an account, sent to staff or recorded as school grades. Download your current review choices before leaving or reloading.

Unit review questions
1. Supplied case 5: voltage (V)=15; resistance (Ω)=3, using the explicitly named quantities. Current in amperes equals volts divided by resistance in ohms. What result follows?
Need a hint?
  • Current in amperes equals volts divided by resistance in ohms.
  • Current and voltage are different physical quantities.
2. Supplied case 5: first resistance (Ω)=7; second resistance (Ω)=9, using the explicitly named quantities. Series equivalent resistance equals the two supplied resistances added. What result follows?
Need a hint?
  • Series equivalent resistance equals the two supplied resistances added.
  • Series elements share current, not necessarily voltage.
3. Supplied case 5: first resistance (Ω)=10; second resistance (Ω)=10, using the explicitly named quantities. Two-resistor parallel equivalent resistance equals their product divided by their sum. What result follows?
Need a hint?
  • Two-resistor parallel equivalent resistance equals their product divided by their sum.
  • The result should be below the smaller branch resistance.
4. Supplied case 5: voltage (V)=15; current (A)=0.5, using the explicitly named quantities. Power in watts equals volts multiplied by amperes. What result follows?
Need a hint?
  • Power in watts equals volts multiplied by amperes.
  • A watt is a joule per second.

The download contains your current choices and any checked feedback. Keep the separate transfer-task work in your own document; downloading its instructions does not mark it complete.

Use the skills in a new task

Create a four-panel explanation for “Circuits, Current and Resistance” using one supplied case from each lesson. Include the observation, scientific mechanism or calculation, result and a limitation. You may draw and speak your explanation; all inputs are supplied.

Work on paper or in your own document. Explain the choices you made.

  • Use one supplied case from each of the four lessons.
  • Name the relevant structure, quantity or process in every panel.
  • Show calculations with units or a causal evidence chain.
  • Distinguish source facts from fictional classroom data.
  • State a model limit or a condition that would change the result.
Compare with a model response

Panel 1: Supplied case 1: voltage (V)=12; resistance (Ω)=4, using the explicitly named quantities. Current in amperes equals volts divided by resistance in ohms. What result follows? Result: 3 A. Reasoning: Substitute the supplied values: (12)/(4) = 3 A. Divide voltage by resistance. The model assumes an ohmic element. Model limitation: only the stated classroom boundary and supplied observations are established; unmeasured real-world performance remains unverified. Panel 2: Supplied case 1: first resistance (Ω)=3; second resistance (Ω)=5, using the explicitly named quantities. Series equivalent resistance equals the two supplied resistances added. What result follows? Result: 8 Ω. Reasoning: Substitute the supplied values: (3)+(5) = 8 Ω. Use this sum only for series connection. No physical circuit is needed. Model limitation: only the stated classroom boundary and supplied observations are established; unmeasured real-world performance remains unverified. Panel 3: Supplied case 1: first resistance (Ω)=4; second resistance (Ω)=4, using the explicitly named quantities. Two-resistor parallel equivalent resistance equals their product divided by their sum. What result follows? Result: 2 Ω. Reasoning: Substitute the supplied values: (4)*(4)/((4)+(4)) = 2 Ω. Do not apply the series sum. Parallel branches share voltage. Model limitation: only the stated classroom boundary and supplied observations are established; unmeasured real-world performance remains unverified. Panel 4: Supplied case 1: voltage (V)=6; current (A)=2, using the explicitly named quantities. Power in watts equals volts multiplied by amperes. What result follows? Result: 12 W. Reasoning: Substitute the supplied values: (6)*(2) = 12 W. Multiply voltage by current. Use hypothetical diagrams, not mains electricity. Model limitation: only the stated classroom boundary and supplied observations are established; unmeasured real-world performance remains unverified.

A different response can also meet the criteria. Compare the evidence and reasoning, rather than copying the wording.