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Grade 11: Science subject test

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1. Supplied case 6: final velocity (m/s)=18; initial velocity (m/s)=6; elapsed time (s)=4, using the explicitly named quantities. Acceleration equals final velocity minus initial velocity, divided by elapsed seconds. What result follows?3 m/s²6 m/s²4 m/s²2 m/s²

2. Supplied case 6: mass (kg)=10; signed acceleration (m/s²)=0.5, using the explicitly named quantities. Net force equals mass in kilograms multiplied by signed acceleration in meters per second squared. What result follows?10.5 N6 N4 N5 N

3. Supplied case 6: initial velocity (m/s)=-2; signed acceleration (m/s²)=-1; elapsed time (s)=3, using the explicitly named quantities. Displacement equals initial velocity times seconds plus one-half acceleration times seconds squared. What result follows?-9.5 m-11.5 m-10.5 m-9 m

4. The cart attracts Earth gravitationally while Earth attracts the cart. What is warranted for the cart diagram? Which inference or prediction is best supported?Equal interaction forces require equal accelerations.Include Earth’s force on the cart, not the cart’s force on Earth.Include both as opposite cart forces.The lighter body has no gravitational interaction.

5. Supplied case 6: mass (kg)=8; speed (m/s)=3, using the explicitly named quantities. Kinetic energy equals one-half mass in kilograms multiplied by speed in meters per second squared. What result follows?24 J37 J35 J36 J

6. Supplied case 6: mass (kg)=8; height increase (m)=2, using the explicitly named quantities. Potential-energy increase equals mass in kilograms times model g of 10 meters per second squared times height increase in meters. What result follows?161 J159 J160 J10 J

7. Supplied case 6: initial mechanical energy (J)=300; thermal transfer (J)=90, using the explicitly named quantities. Remaining mechanical energy equals initial mechanical energy minus thermal transfer. What result follows?209 J210 J390 J211 J

8. An interacting third cart is omitted from a claimed isolated two-cart system. What follows? Which inference or prediction is best supported?Momentum can cross the chosen boundary, so the two-cart conservation claim needs revision.Omitting an interaction strengthens isolation.Every subsystem conserves momentum regardless of external forces.Lost subsystem momentum means total matter vanished.

9. Supplied case 6: voltage (V)=20; resistance (Ω)=10, using the explicitly named quantities. Current in amperes equals volts divided by resistance in ohms. What result follows?3 A1 A2 A200 A

10. Supplied case 6: first resistance (Ω)=10; second resistance (Ω)=15, using the explicitly named quantities. Series equivalent resistance equals the two supplied resistances added. What result follows?24 Ω25 Ω150 Ω26 Ω

11. Supplied case 6: first resistance (Ω)=9; second resistance (Ω)=18, using the explicitly named quantities. Two-resistor parallel equivalent resistance equals their product divided by their sum. What result follows?6 Ω27 Ω7 Ω5 Ω

12. Supplied case 6: voltage (V)=20; current (A)=1.2, using the explicitly named quantities. Power in watts equals volts multiplied by amperes. What result follows?16.666667 W25 W23 W24 W

13. Supplied case 6: temperature (°C)=60, using the explicitly named quantities. Kelvin temperature equals Celsius temperature plus 273.15. What result follows?332.15 K333.15 K-213.15 K334.15 K

14. Supplied case 6: mass (kg)=5; specific heat (J/(kg·K))=80; temperature increase (K)=3, using the explicitly named quantities. Energy transferred equals kilograms times supplied joules per kilogram-kelvin times temperature change in kelvin. What result follows?1200 J403 J1201 J1199 J

15. Supplied case 6: initial pressure (kPa)=110; final temperature (K)=330; initial temperature (K)=300, using the explicitly named quantities. Final pressure equals initial pressure times final kelvin temperature divided by initial kelvin temperature. What result follows?10890000 kPa122 kPa120 kPa121 kPa

16. An insulated gas is compressed and gains internal energy with no thermal transfer. Which mechanism fits? Which inference or prediction is best supported?No energy transfer occurred because heat was zero.Compression creates energy from nothing.Work transfers energy through mechanical compression.Heat must be a substance stored inside.

17. Supplied case 6: wave speed (m/s)=60; frequency (Hz)=10, using the explicitly named quantities. Wavelength in meters equals wave speed in meters per second divided by frequency in hertz. What result follows?6 m600 m7 m5 m

18. Supplied case 6: incidence angle from normal (degrees)=65, using the explicitly named quantities. Reflection angle from the normal equals supplied incidence angle from the normal. What result follows?25 degrees66 degrees64 degrees65 degrees

19. At one point displacements are+4 and−1 mm. What follows? Which inference or prediction is best supported?The result is−5 mm.All wave energy is destroyed everywhere.The result is+3 mm; partial cancellation is not total disappearance.The result is zero for all opposite signs.

20. Instrument A separates 0.2 mm apart features; B requires 0.5 mm under matched conditions. What fits? Which inference or prediction is best supported?Spacing alone establishes every image’s magnification.A has finer resolving ability in that stated comparison.B resolves finer because 0.5 is larger.Both must resolve every possible feature.

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