Grade 11 · lesson 3 of 4

Combine two parallel resistances

Combine two parallel resistances using supplied evidence and a solved model.

About 25 minutes, plus any extended practice

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Supplied materials

  • All measurements and observations below are supplied classroom examples. They are not data from actual learners or a claim about a particular real site.
  • Paper or browser document; an ordinary calculator is optional.
  • Rule: Two-resistor parallel equivalent resistance equals their product divided by their sum. Formula: a*b/(a+b). Variable key: a = first resistance (Ω), b = second resistance (Ω)
  • Distinct worked inputs and result: A distinct parallel model has 2 Ω and 2 Ω: (2×2)/(2+2)=1 Ω.
  • Assessment case 1: Supplied case 1: first resistance (Ω)=4; second resistance (Ω)=4, using the explicitly named quantities. Two-resistor parallel equivalent resistance equals their product divided by their sum. What result follows?
  • Assessment case 2: Supplied case 2: first resistance (Ω)=6; second resistance (Ω)=3, using the explicitly named quantities. Two-resistor parallel equivalent resistance equals their product divided by their sum. What result follows?
  • Assessment case 3: Supplied case 3: first resistance (Ω)=8; second resistance (Ω)=8, using the explicitly named quantities. Two-resistor parallel equivalent resistance equals their product divided by their sum. What result follows?
  • Assessment case 4: Supplied case 4: first resistance (Ω)=12; second resistance (Ω)=6, using the explicitly named quantities. Two-resistor parallel equivalent resistance equals their product divided by their sum. What result follows?
  • Assessment case 5: Supplied case 5: first resistance (Ω)=10; second resistance (Ω)=10, using the explicitly named quantities. Two-resistor parallel equivalent resistance equals their product divided by their sum. What result follows?
  • Assessment case 6: Supplied case 6: first resistance (Ω)=9; second resistance (Ω)=18, using the explicitly named quantities. Two-resistor parallel equivalent resistance equals their product divided by their sum. What result follows?

Learn the idea

Parallel branches share voltage. For two ideal resistors, reciprocal resistances add, yielding equivalent resistance smaller than either positive branch resistance. This is an idealized model.

Two-resistor parallel equivalent resistance equals their product divided by their sum. The formula in the supplied model is a*b/(a+b). Variable key: a = first resistance (Ω), b = second resistance (Ω). Do not apply the series sum. The result should be below the smaller branch resistance.

A distinct parallel model has 2 Ω and 2 Ω: (2×2)/(2+2)=1 Ω. Parallel branches share voltage. Track the quantity and unit before calculating. Explain the meaning of a positive, negative or fractional result when relevant. A numerical answer supports the stated model calculation; broader claims require the additional measurements and assumptions described here.

  1. Name the measured quantities and their units before substituting values.
  2. Write the stated rule and use the variable key to match each symbol to its explicitly named quantity.
  3. Calculate each supplied case separately, keeping intermediate arithmetic and the result unit.
  4. Explain the result in context and identify the assumption that would invalidate direct use of the rule.
Worked example

See the method in action

Worked distinct example: A distinct parallel model has 2 Ω and 2 Ω: (2×2)/(2+2)=1 Ω. Method: identify the quantities in the stated rule, substitute using compatible units, and perform the operations in the correct order. Do not apply the series sum. The result should be below the smaller branch resistance. Interpret the final unit and keep the model assumption visible; this calculation is not a measurement of a real learner or site.

Your turn

Check your reasoning

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Helpful tips
  • Do not apply the series sum.
  • The result should be below the smaller branch resistance.
Supplied case 1: first resistance (Ω)=4; second resistance (Ω)=4, using the explicitly named quantities. Two-resistor parallel equivalent resistance equals their product divided by their sum. What result follows?

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See the answer and explanation

2 Ω

Substitute the supplied values: (4)*(4)/((4)+(4)) = 2 Ω. Do not apply the series sum. Parallel branches share voltage.

Take it further

Changed-input task: use the same stated model with first resistance (Ω)=5; second resistance (Ω)=4. Expected result: approximately 2.2222222 Ω. Explain what changes and keep this assumption: Parallel branches share voltage.

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More practice: try new cases

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More practice: try new cases
1. Supplied case 2: first resistance (Ω)=6; second resistance (Ω)=3, using the explicitly named quantities. Two-resistor parallel equivalent resistance equals their product divided by their sum. What result follows?
Need a hint?
  • Two-resistor parallel equivalent resistance equals their product divided by their sum.
  • The result should be below the smaller branch resistance.
2. Supplied case 3: first resistance (Ω)=8; second resistance (Ω)=8, using the explicitly named quantities. Two-resistor parallel equivalent resistance equals their product divided by their sum. What result follows?
Need a hint?
  • Two-resistor parallel equivalent resistance equals their product divided by their sum.
  • The result should be below the smaller branch resistance.
3. Supplied case 4: first resistance (Ω)=12; second resistance (Ω)=6, using the explicitly named quantities. Two-resistor parallel equivalent resistance equals their product divided by their sum. What result follows?
Need a hint?
  • Two-resistor parallel equivalent resistance equals their product divided by their sum.
  • The result should be below the smaller branch resistance.

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