Grade 11 · lesson 2 of 4

Read a Focus from a Standard Parabola

The vertical parabola x²=4py consists of points equally distant from focus (0,p) and directrix y=−p.

About 25 minutes, plus any extended practice

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Supplied materials

  • Paper or a browser scratch area; a calculator is optional unless rounding is requested.
  • Supplied teaching case: For x²=8y, find the focus. Candidate answers: (A) (0,2) (B) (0,8) (C) (0,−2) (D) (2,0).
  • Independent check inputs: For x²=12y, find the focus. Candidate answers: (A) (0,12) (B) (0,3) (C) (0,−3) (D) (3,0).

Learn the idea

Circle, parabola, ellipse and hyperbola equations encode geometric features through squared quantities and sign patterns. Standard forms locate centers, focal information, axes or vertices, with care to distinguish full lengths from half lengths. The vertical parabola x²=4py consists of points equally distant from focus (0,p) and directrix y=−p. The coefficient four p determines the focal distance and opening direction.

Here is the method on the supplied teaching case. The standard vertical parabola form x²=4py has focus (0,p) and directrix y=−p. Thus p=8/4=2, and the focus is (0,2).

Divide the y coefficient by four to identify p. A focus is not the vertex: the unshifted vertex here is the origin, and positive p places the focus above it.

  1. Write or sketch the supplied teaching case, labeling its quantities and restrictions.
  2. Apply the method shown in the worked solution, keeping each intermediate equality or justified inference.
  3. Solve the independent check with its changed inputs before revealing feedback.
  4. Complete the three practice cases; explain which mathematical rule rules out one distractor in each case.
Worked example

See the method in action

Teaching case: For x²=8y, find the focus. Candidate answers: (A) (0,2) (B) (0,8) (C) (0,−2) (D) (2,0). Solution: The standard vertical parabola form x²=4py has focus (0,p) and directrix y=−p. Thus p=8/4=2, and the focus is (0,2). The final answer is (0,2). Divide the y coefficient by four to identify p. A focus is not the vertex: the unshifted vertex here is the origin, and positive p places the focus above it.

Your turn

Check your reasoning

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Helpful tips
  • The vertical parabola x²=4py consists of points equally distant from focus (0,p) and directrix y=−p.
  • Divide the y coefficient by four to identify p.
For x²=12y, find the focus.

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See the answer and explanation

(0,3)

The standard vertical parabola form x²=4py has focus (0,p) and directrix y=−p. Thus p=12/4=3, and the focus is (0,3).

Take it further

Changed-input task: For x²=36y, find the focus. Candidate answers: (A) (0,36) (B) (0,9) (C) (0,−9) (D) (9,0). Show the mathematical reason, not only the selected answer. Expected result: (0,9). The standard vertical parabola form x²=4py has focus (0,p) and directrix y=−p. Thus p=36/4=9, and the focus is (0,9).

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More practice: try new cases

Choose an answer for each problem. Explain your method on paper, then use the feedback to decide what to revisit.

More practice: try new cases
1. For x²=16y, find the focus.
Need a hint?
  • The vertical parabola x²=4py consists of points equally distant from focus (0,p) and directrix y=−p.
  • Divide the y coefficient by four to identify p.
2. For x²=20y, find the focus.
Need a hint?
  • The vertical parabola x²=4py consists of points equally distant from focus (0,p) and directrix y=−p.
  • Divide the y coefficient by four to identify p.
3. For x²=24y, find the focus.
Need a hint?
  • The vertical parabola x²=4py consists of points equally distant from focus (0,p) and directrix y=−p.
  • Divide the y coefficient by four to identify p.

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