Grade 10 · lesson 1 of 4

Find a rectangle’s largest modelled area

Connect a quadratic expression with a table and a constrained maximum.

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Supplied materials

  • Fictional paper rectangle has width w and length 10 − w, measured in units. For this model, 0 ≤ w ≤ 10; zero gives a collapsed boundary shape.
  • Area rule: A(w) = w(10 − w) = 10w − w². You need multiplication and squares.

Learn the idea

The area is quadratic because multiplying w by 10 − w produces a squared term. Unlike a linear rule, equal increases in width do not produce a constant area increase.

The expression can also be written A(w) = 25 − (w − 5)². Since a square cannot be negative, the area cannot exceed 25 in this model, and that value occurs when w = 5.

  1. Calculate area at widths 2, 5 and 8.
  2. Compare widths equally far from 5.
  3. Use the completed-square form to explain the maximum.
  4. Calculate the changed width in the question.
Worked example

See the method in action

A(2) = 2 × 8 = 16; A(5) = 5 × 5 = 25; A(8) = 8 × 2 = 16 square units. The equal areas at 2 and 8 reflect symmetry around w = 5.

Your turn

Check your reasoning

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What area does the model give when w = 3?

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See the answer and explanation

21 square units

A(3) = 3(10 − 3) = 3 × 7 = 21. In the other form, 25 − (3 − 5)² = 25 − 4 = 21, providing an independent check.

Take it further

Change the fixed width-plus-length total from 10 to 12. Show that A(w) = 36 − (w − 6)² and the maximum is 36 at w = 6.

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Longer courses for learners ages 14+

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