Grade 10 · lesson 4 of 4

Connect pH and pOH at 25°C

Connect pH and pOH at 25°C using supplied evidence and a solved model.

About 25 minutes, plus any extended practice

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Supplied materials

  • All measurements and observations below are supplied classroom examples. They are not data from actual learners or a claim about a particular real site.
  • Paper or browser document; an ordinary calculator is optional.
  • Rule: At stated 25°C, pOH equals 14 minus pH. Formula: 14-a. Variable key: a = pH at 25°C
  • Distinct worked inputs and result: A distinct 25°C model has pH 4: pOH=14-4=10.
  • Assessment case 1: Supplied case 1: pH at 25°C=2, using the explicitly named quantities. At stated 25°C, pOH equals 14 minus pH. What result follows?
  • Assessment case 2: Supplied case 2: pH at 25°C=3, using the explicitly named quantities. At stated 25°C, pOH equals 14 minus pH. What result follows?
  • Assessment case 3: Supplied case 3: pH at 25°C=5, using the explicitly named quantities. At stated 25°C, pOH equals 14 minus pH. What result follows?
  • Assessment case 4: Supplied case 4: pH at 25°C=6, using the explicitly named quantities. At stated 25°C, pOH equals 14 minus pH. What result follows?
  • Assessment case 5: Supplied case 5: pH at 25°C=8, using the explicitly named quantities. At stated 25°C, pOH equals 14 minus pH. What result follows?
  • Assessment case 6: Supplied case 6: pH at 25°C=11, using the explicitly named quantities. At stated 25°C, pOH equals 14 minus pH. What result follows?

Learn the idea

For idealized dilute water-based solutions at 25°C, pH+pOH is approximately 14. The relationship changes with temperature because water’s ion-product constant changes.

At stated 25°C, pOH equals 14 minus pH. The formula in the supplied model is 14-a. Variable key: a = pH at 25°C. Keep the 25°C condition. pOH concerns hydroxide rather than hydronium.

A distinct 25°C model has pH 4: pOH=14-4=10. Do not apply a constant fourteen at every temperature. Track the quantity and unit before calculating. Explain the meaning of a positive, negative or fractional result when relevant. A numerical answer supports the stated model calculation; broader claims require the additional measurements and assumptions described here.

  1. Name the measured quantities and their units before substituting values.
  2. Write the stated rule and use the variable key to match each symbol to its explicitly named quantity.
  3. Calculate each supplied case separately, keeping intermediate arithmetic and the result unit.
  4. Explain the result in context and identify the assumption that would invalidate direct use of the rule.
Worked example

See the method in action

Worked distinct example: A distinct 25°C model has pH 4: pOH=14-4=10. Method: identify the quantities in the stated rule, substitute using compatible units, and perform the operations in the correct order. Keep the 25°C condition. pOH concerns hydroxide rather than hydronium. Interpret the final unit and keep the model assumption visible; this calculation is not a measurement of a real learner or site.

Your turn

Check your reasoning

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Helpful tips
  • Keep the 25°C condition.
  • pOH concerns hydroxide rather than hydronium.
Supplied case 1: pH at 25°C=2, using the explicitly named quantities. At stated 25°C, pOH equals 14 minus pH. What result follows?

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See the answer and explanation

12 pOH units

Substitute the supplied values: 14-(2) = 12 pOH units. Keep the 25°C condition. Do not apply a constant fourteen at every temperature.

Take it further

Changed-input task: use the same stated model with pH at 25°C=3. Expected result: 11 pOH units. Explain what changes and keep this assumption: Do not apply a constant fourteen at every temperature.

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More practice: try new cases

Choose an answer for each problem. Explain your method on paper, then use the feedback to decide what to revisit.

More practice: try new cases
1. Supplied case 2: pH at 25°C=3, using the explicitly named quantities. At stated 25°C, pOH equals 14 minus pH. What result follows?
Need a hint?
  • At stated 25°C, pOH equals 14 minus pH.
  • pOH concerns hydroxide rather than hydronium.
2. Supplied case 3: pH at 25°C=5, using the explicitly named quantities. At stated 25°C, pOH equals 14 minus pH. What result follows?
Need a hint?
  • At stated 25°C, pOH equals 14 minus pH.
  • pOH concerns hydroxide rather than hydronium.
3. Supplied case 4: pH at 25°C=6, using the explicitly named quantities. At stated 25°C, pOH equals 14 minus pH. What result follows?
Need a hint?
  • At stated 25°C, pOH equals 14 minus pH.
  • pOH concerns hydroxide rather than hydronium.

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