Calculate molar concentration
Calculate molar concentration using supplied evidence and a solved model.
About 25 minutes, plus any extended practice
Supplied materials
- All measurements and observations below are supplied classroom examples. They are not data from actual learners or a claim about a particular real site.
- Paper or browser document; an ordinary calculator is optional.
- Rule: Molarity equals solute moles divided by solution liters. Formula: a/b. Variable key: a = solute amount (mol), b = solution volume (L)
- Distinct worked inputs and result: A distinct solution model has 0.9 mol in 3 L: 0.9/3=0.3 mol/L.
- Assessment case 1: Supplied case 1: solute amount (mol)=0.6; solution volume (L)=2, using the explicitly named quantities. Molarity equals solute moles divided by solution liters. What result follows?
- Assessment case 2: Supplied case 2: solute amount (mol)=1.2; solution volume (L)=3, using the explicitly named quantities. Molarity equals solute moles divided by solution liters. What result follows?
- Assessment case 3: Supplied case 3: solute amount (mol)=0.8; solution volume (L)=4, using the explicitly named quantities. Molarity equals solute moles divided by solution liters. What result follows?
- Assessment case 4: Supplied case 4: solute amount (mol)=1.5; solution volume (L)=5, using the explicitly named quantities. Molarity equals solute moles divided by solution liters. What result follows?
- Assessment case 5: Supplied case 5: solute amount (mol)=2.4; solution volume (L)=6, using the explicitly named quantities. Molarity equals solute moles divided by solution liters. What result follows?
- Assessment case 6: Supplied case 6: solute amount (mol)=3.5; solution volume (L)=7, using the explicitly named quantities. Molarity equals solute moles divided by solution liters. What result follows?
Learn the idea
Molarity is moles of solute per liter of solution, not per liter of solvent before mixing. Use supplied hypothetical measurements only; no chemical preparation is required.
Molarity equals solute moles divided by solution liters. The formula in the supplied model is a/b. Variable key: a = solute amount (mol), b = solution volume (L). Use final solution volume. Moles and grams are different units.
A distinct solution model has 0.9 mol in 3 L: 0.9/3=0.3 mol/L. Do not assume solute volume is zero in actual preparation. Track the quantity and unit before calculating. Explain the meaning of a positive, negative or fractional result when relevant. A numerical answer supports the stated model calculation; broader claims require the additional measurements and assumptions described here.
- Name the measured quantities and their units before substituting values.
- Write the stated rule and use the variable key to match each symbol to its explicitly named quantity.
- Calculate each supplied case separately, keeping intermediate arithmetic and the result unit.
- Explain the result in context and identify the assumption that would invalidate direct use of the rule.
See the method in action
Worked distinct example: A distinct solution model has 0.9 mol in 3 L: 0.9/3=0.3 mol/L. Method: identify the quantities in the stated rule, substitute using compatible units, and perform the operations in the correct order. Use final solution volume. Moles and grams are different units. Interpret the final unit and keep the model assumption visible; this calculation is not a measurement of a real learner or site.
Check your reasoning
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Helpful tips
- Use final solution volume.
- Moles and grams are different units.
See the answer and explanation
0.3 mol/L
Substitute the supplied values: (0.6)/(2) = 0.3 mol/L. Use final solution volume. Do not assume solute volume is zero in actual preparation.
Take it further
Changed-input task: use the same stated model with solute amount (mol)=1.6; solution volume (L)=2. Expected result: 0.8 mol/L. Explain what changes and keep this assumption: Do not assume solute volume is zero in actual preparation.
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More practice: try new cases
Choose an answer for each problem. Explain your method on paper, then use the feedback to decide what to revisit.
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