Interpret Mass per Unit Volume
Density compares total mass with occupied volume.
About 20 minutes, plus any extended practice
Supplied materials
- Paper or a browser scratch area; a calculator is optional unless rounding is requested.
- Supplied teaching case: A fictional uniform block has mass 24 grams and volume 6 cm³. Find its density. Candidate answers: (A) 1/4 g/cm³ (B) 144 g/cm³ (C) 24 g/cm³ (D) 4 g/cm³.
- Independent check inputs: A fictional uniform block has mass 45 grams and volume 9 cm³. Find its density. Candidate answers: (A) 1/5 g/cm³ (B) 405 g/cm³ (C) 45 g/cm³ (D) 5 g/cm³.
Learn the idea
Geometry can support probability, material, density and layout models when the assumptions are explicit. Ratios and decompositions must use nonoverlapping regions, consistent dimensions and the correct uniformity or exact-fit conditions. Density compares total mass with occupied volume. A supplied uniform-block model uses one constant mass-per-volume ratio, allowing the ratio to be calculated from its complete measurements.
Here is the method on the supplied teaching case. Density=mass/volume=24/6=4 g/cm³. The ratio names mass in one cubic centimeter, not the block’s total mass.
Dividing volume by mass gives a reciprocal unit and a different quantity. Label both inputs before calculating; a uniform fictional block does not establish the density of all real materials.
- Write or sketch the supplied teaching case, labeling its quantities and restrictions.
- Apply the method shown in the worked solution, keeping each intermediate equality or justified inference.
- Solve the independent check with its changed inputs before revealing feedback.
- Complete the three practice cases; explain which mathematical rule rules out one distractor in each case.
See the method in action
Teaching case: A fictional uniform block has mass 24 grams and volume 6 cm³. Find its density. Candidate answers: (A) 1/4 g/cm³ (B) 144 g/cm³ (C) 24 g/cm³ (D) 4 g/cm³. Solution: Density=mass/volume=24/6=4 g/cm³. The ratio names mass in one cubic centimeter, not the block’s total mass. The final answer is 4 g/cm³. Dividing volume by mass gives a reciprocal unit and a different quantity. Label both inputs before calculating; a uniform fictional block does not establish the density of all real materials.
Check your reasoning
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Helpful tips
- Density compares total mass with occupied volume.
- Dividing volume by mass gives a reciprocal unit and a different quantity.
See the answer and explanation
5 g/cm³
Density=mass/volume=45/9=5 g/cm³. The ratio names mass in one cubic centimeter, not the block’s total mass.
Take it further
Changed-input task: A fictional uniform block has mass 297 grams and volume 27 cm³. Find its density. Candidate answers: (A) 1/11 g/cm³ (B) 11 g/cm³ (C) 297 g/cm³ (D) 8019 g/cm³. Show the mathematical reason, not only the selected answer. Expected result: 11 g/cm³. Density=mass/volume=297/27=11 g/cm³. The ratio names mass in one cubic centimeter, not the block’s total mass.
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More practice: try new cases
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