Compare a fixed-force lever change
Compare a fixed-force lever change
About 18 minutes, plus any extended practice
Supplied materials
- Paper or a text document; all cases below are original fictional learning inputs.
- An adult may read aloud; drawing or spoken answers are valid. No personal health information or physical performance is required.
- The separate worked case gives newMeters=0.75, oldMeters=0.25. With force held constant, divide new perpendicular distance by old distance. First identify the quantities and keep their units consistent. The calculation is 0.75/0.25=3 times the modeled torque. Round to six decimal places where needed. That result answers this supplied planning question only. It does not establish what a real person did, diagnose a condition or prove physical skill. Compare the units with the question before accepting a number.
- Fictional case 1: newMeters=0.4, oldMeters=0.2. What is the modeled result using the stated method?
- Fictional case 2: newMeters=0.6, oldMeters=0.3. What is the modeled result using the stated method?
- Fictional case 3: newMeters=0.3, oldMeters=0.1. What is the modeled result using the stated method?
- Fictional case 4: newMeters=0.8, oldMeters=0.4. What is the modeled result using the stated method?
- Fictional case 5: newMeters=0.5, oldMeters=0.25. What is the modeled result using the stated method?
- Fictional case 6: newMeters=0.9, oldMeters=0.3. What is the modeled result using the stated method?
Learn the idea
A ratio compares two model turning effects under the same force. Because torque is force times perpendicular distance, the force cancels in the ratio when it is genuinely unchanged. A longer distance then has a proportional modeled effect.
Divide new perpendicular distance by old distance. A ratio of two means twice the modeled torque, not two extra newton-meters. If force changes too, this simple ratio no longer isolates the distance effect.
Use paper diagrams only. No real lever, lifting or body test is required. This idealized comparison teaches mechanics and controlled conditions, not whether a physical technique is safe or appropriate for a person.
- Mark the facts or constraints in the supplied case.
- Apply the method explained above; draw a sequence, table or decision map.
- Compare your result with the worked solution and explain the difference.
- Complete the new cases, then check the changed-case extension.
See the method in action
The separate worked case gives newMeters=0.75, oldMeters=0.25. With force held constant, divide new perpendicular distance by old distance. First identify the quantities and keep their units consistent. The calculation is 0.75/0.25=3 times the modeled torque. Round to six decimal places where needed. That result answers this supplied planning question only. It does not establish what a real person did, diagnose a condition or prove physical skill. Compare the units with the question before accepting a number.
Check your reasoning
Your answer is temporary and is not saved to an account. Download your current answer before leaving or reloading. Written work on paper or in another app stays in your own file.
Helpful tips
- The cancellation is valid only when the force is unchanged.
- A multiplicative comparison is different from an additive unit difference.
See the answer and explanation
2 times the modeled torque
With force held constant, divide new perpendicular distance by old distance. With newMeters=0.4, oldMeters=0.2, calculate 0.4/0.2=2 times the modeled torque. Results are rounded to six decimal places where needed. This is a supplied model, not a personal health assessment.
Take it further
Changed case: newMeters=0.6, oldMeters=0.2. Show the operation. Expected: 0.6/0.2=3 times the modeled torque; round to six decimal places where needed, retain model limits and explain the units.
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More practice: try new cases
Choose an answer for each problem. Explain your method on paper, then use the feedback to decide what to revisit.
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Check the subject sources
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