Read acceleration from velocity change
See this course’s project requirements
A fictional cart-motion report with position and velocity graphs, net-force reasoning, a mass/acceleration comparison and a checked prediction.
Keep your working files in your own notebook or software. Save a private description, checklist, and work link in My Proof.
What to include
- Define a reference frame and calculate distance versus displacement.
- Plot the supplied position-time graph and compute both averages.
- Calculate acceleration from velocity change.
- Draw a one-object force diagram and sum components.
- Compare masses under fixed net force.
- Test the final prediction against supplied data and include changed cases.
Review and revise
Use these criteria to check your work and choose what to improve.
- Method: applies the course-specific rules to the supplied cases with visible intermediate work.
- Accuracy: results agree with the stated facts, units, boundaries and independent checks.
- Reasoning: explains why the result follows and identifies a limitation or unresolved question.
- Transfer: completes changed cases and revises the final project when a relevant assumption changes.
Want more background?
The idea in everyday life
Supplied velocity record for one straight-line interval: t=0 s, v=2 m/s east; t=3 s, v=8 m/s east. East is positive and acceleration is constant over the interval.
Average acceleration equals change in velocity divided by elapsed time. Its units are meters per second per second. A negative acceleration is not automatically slowing: compare its direction with velocity. For a positive-moving object, negative acceleration reduces positive velocity over the stated interval.
Read acceleration from velocity change — worked practice
Average acceleration equals change in velocity divided by elapsed time. Its units are meters per second per second. A negative acceleration is not automatically slowing: compare its direction with velocity. For a positive-moving object, negative acceleration reduces positive velocity over the stated interval.
Supplied velocity record for one straight-line interval: t=0 s, v=2 m/s east; t=3 s, v=8 m/s east. East is positive and acceleration is constant over the interval.
1. 1. Change
Subtract initial velocity from final velocity.
You should see: 8−2=+6 m/s.
2. 2. Rate
Divide the change by elapsed time.
You should see: a=6/3=+2 m/s².
3. 3. Predict
Use v=v0+at at t=2 s under the stated constant acceleration.
You should see: v=2+2×2=6 m/s east.
4. 4. Compare
Consider a separate interval with v=8 to 2 m/s east over 3 s.
You should see: Acceleration is−2 m/s² and speed decreases in this positive-moving case.
What to finish
A velocity-change calculation and labeled velocity-time segment.
Watch for this
An object already moving in the negative direction can speed up with negative acceleration. Compare velocity and acceleration directions instead of using the sign alone.
How can I tell I understand it?
Recalculate a changed interval without treating final velocity as the velocity change.
Quick knowledge check
Answer all 3 questions. Get at least 2 right and the lesson completes automatically.
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Answer all 3 questions above and get at least 2 right. You can review the explanations and try again.
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Source & access notes · checked 2026-10-01
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